1 y = 2x^2 3 y = 3x 1 both right sides are equal to y, so they must be equal to each other 2x^2 3 = 3x 1 2x^2 3x 2 = 0 this factors nicely 2 0 = 3x^2 x 4 3x^2 x 4 = 0 , a=3, b= 1, c = 4 b^2 4ac = 1 4(3)(4) = 47 you would be dealing with √47 which is not a real number, so what do you think? Solve each system using elimination 1) 5x y=0 3x y=24 2) 3x 3y =27 x 3y =11 3) 6x 4y =42 3x 3y =6 math solve the system ofAnswer (1 of 3) Yes, as Jan van Delden has noted, we could use matrix notation and invert the matrix Or, here's the oldfashioned solution by substitution (to demonstrate the steps) 3x 2y 2z = 2 (1) 2x y – z = 2 (2) x 3y z = 0 (3) From (3) z = x 3y sub this value i
Solved Solve Each System Using Elimination 1 Xty 2 2 X 2y 3 3 2x Y 4 X Y 4 X Y 6 3x Y 2 4 X 2y 2 5 X 3y 3 6 X Course Hero
